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Eigenfunctions and Eigenvalues

An eigenfunction of an operator $\hat{A}$ is a function f such that the application of $\hat{A}$ on f gives f again, times a constant.

\begin{displaymath}\hat{A} f = k f
\end{displaymath} (49)

where k is a constant called the eigenvalue. It is easy to show that if $\hat{A}$ is a linear operator with an eigenfunction g, then any multiple of g is also an eigenfunction of $\hat{A}$.

When a system is in an eigenstate of observable A (i.e., when the wavefunction is an eigenfunction of the operator $\hat{A}$) then the expectation value of A is the eigenvalue of the wavefunction. Thus if

\begin{displaymath}\hat{A} \psi({\bf r}) = a \psi({\bf r})
\end{displaymath} (50)

then
<A> = $\displaystyle \int \psi^{*}({\bf r}) \hat{A} \psi({\bf r})$ (51)
  = $\displaystyle \int \psi^{*}({\bf r}) a \psi({\bf r})$  
  = $\displaystyle a \int \psi^{*}({\bf r}) \psi({\bf r})$  
  = a  

assuming that the wavefunction is normalized to 1, as is generally the case. In the event that $\psi({\bf r})$ is not or cannot be normalized (free particle, etc.) then we may use the formula

\begin{displaymath}<A> = \frac{\int \psi^{*}({\bf r}) \hat{A} \psi({\bf r})}
{\int \psi^{*}({\bf r}) \psi({\bf r})}
\end{displaymath} (52)

What if the wavefunction is a combination of eigenstates? Let us assume that we have a wavefunction which is a linear combination of two eigenstates of $\hat{A}$ with eigenvalues a and b.

\begin{displaymath}\psi = c_a \psi_a + c_b \psi_b
\end{displaymath} (53)

where $\hat{A} \psi_a = a \psi_a$ and $\hat{A} \psi_b = b \psi_b$. Then what is the expectation value of A?
<A> = $\displaystyle \int \psi^{*} \hat{A} \psi$ (54)
  = $\displaystyle \int \left[ c_a \psi_a + c_b \psi_b \right]^{*} \hat{A}
\left[ c_a \psi_a + c_b \psi_b \right]$  
  = $\displaystyle \int \left[ c_a \psi_a + c_b \psi_b \right]^{*}
\left[ a c_a \psi_a + b c_b \psi_b \right]$  
  = $\displaystyle a \vert c_a\vert^2 \int \psi_a^{*} \psi_a +
b c_a^{*} c_b \int \p...
... c_b^{*} c_a \int \psi_b^{*} \psi_a +
b \vert c_b\vert^2 \int \psi_b^{*} \psi_b$  
  = a |ca|2 + b |cb|2  

assuming that $\psi_a$ and $\psi_b$ are orthonormal (shortly we will show that eigenvectors of Hermitian operators are orthogonal). Thus the average value of A is a weighted average of eigenvalues, with the weights being the squares of the coefficients of the eigenvectors in the overall wavefunction.


next up previous contents
Next: Hermitian Operators Up: Operators Previous: Linear Operators