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Now consider a particle subject to a restoring force F = -kx, as might
arise for a mass-spring system obeying Hooke's Law. The potential is
then
V(x) |
= |
 |
(118) |
|
= |
 |
|
If we choose the energy scale such that V0 = 0 then
V(x) =
(1/2)kx2. This potential is also appropriate for describing the
interaction of two masses connected by an ideal spring. In this case,
we let x be the distance between the masses, and for the mass m we
substitute the reduced mass
.
Thus the harmonic oscillator is
the simplest model for the vibrational motion of the atoms in a
diatomic molecule, if we consider the two atoms as point masses and
the bond between them as a spring. The one-dimensional Schrödinger
equation becomes
 |
(119) |
After some effort, the eigenfunctions are
 |
(120) |
where Hn is the Hermite polynomial of degree n, and
and
Nn are defined by
 |
(121) |
The eigenvalues are
 |
(122) |
with
.
Next: The Rigid Rotor
Up: Some Analytically Soluble Problems
Previous: The Particle in a